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Mathematics 20 Online
AlexisR:

so i just did a math problom with this 2*(x-4)=2 2X-8=2 2X=2+8 2X=10 X=10/2 X=5 how do i get one of these resolts s=(3;5) s=(2;6) s=(1;3)

Timmyspu:

Ok so do you know how to get y by its self?

AlexisR:

hmm no not really its ben sum time sence ive done this

snowflake0531:

Can you screenshot the whole question? Maybe you're interpreting the question wrong, so you aren't getting any of the choices

Timmyspu:

You solved for x correct?

AlexisR:

it whas in spanish so this a rogh translation The solution set of the following equation with modulus is:

snowflake0531:

Just with the word modulus, we're obviously missing some kind of information

Timmyspu:

@snowflake0531 wrote:
Can you screenshot the whole question? Maybe you're interpreting the question wrong, so you aren't getting any of the choices
A screen shot would help us a lot so could we get a screen shot?

Timmyspu:

Also welcome to question cove AlexisR if you have any questions feel free to ask.

AlexisR:

the bottom one im confused on 2

Timmyspu:

On question two?

Timmyspu:

If you are talking about on the link that you gave us there is no question 2.

AlexisR:

no i did n2 3) 4) im having a hard time

Timmyspu:

@snowflake0531 can you help me?

snowflake0531:

You made one mistake, the | is absolute value, not parenthesis Do you know what absolute value is?

AlexisR:

no?? can u elaborate?

snowflake0531:

Uh, absolute value is easier explained in examples |2| = 2 |-3| = 3 |-83|=83 |47| = 47 yeah? so it just makes it positive... kinda

snowflake0531:

So for \(2 \times |x-4|=2\) I suggest first isolating the |x-4| so then it becomes \(|x-4|=1\)

AlexisR:

man this is new stuff for me thay never teachd me this back in school

snowflake0531:

So then from there split in into two equations \(x-4=1\) and \(x-4 = -1\)

snowflake0531:

from there, you can get your 2 x values

snowflake0531:

@alexisr wrote:
man this is new stuff for me thay never teachd me this back in school
welp, learn it now then xd

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