Question

I forgot what to do ...

SS below

Answer 1

To find the arc length for ex #4 r= 14 yd. 0 = 225 do
\[225.(14yrd).\frac{ 2\pi}{ 360 }\]

Answer 2

so 54.95 ?

Answer 3

Evaluated that problem would be
\[\frac{ 35dy \pi }{ 2}\]

Answer 4

i got the same answer...

Answer 5

Well thank you . I think I got the rest.

Answer 6

4 is asking you to find the AREA of it

whatever that person above did, its wrong

Answer 7

it would look like this if you were to solve it right:

\[ A=\frac{\theta}{360}\times \pi \times r^2 \]
thus,
\[ A= \frac{225}{360}\times 3.14 \times 14^2 \]
\[ A=\frac{225}{360}\times 3.14 \times 196 \]
\[ A=\frac{225}{360}\times 3.14 \times 196 \]
\[ A=\frac{225}{360}\times 615.44 \]
\[ A \approx 384.7 \ \ yd^2 \]