Ask your own question, for FREE!
Mathematics 19 Online
Vermillions:

The graph below is a parabola, so it can be represented by a quadratic function. Which of the following quadratic functions could represent this graph? y = -( x + 2) 2 + 4 y = ( x - 2) 2 + 4 y = -( x - 2) 2 - 4 y = -( x - 2) 2 + 4

jhonyy9:

please post the graph

Vermillions:

mhanifa:

Do you know the standard form of quadratic function?

Vermillions:

@mhanifa wrote:
Do you know the standard form of quadratic function?
Yes I do

mhanifa:

Can you add it here please?

mhanifa:

The vertex form

Vermillions:

@mhanifa wrote:
Can you add it here please?
The standard function or for this equation?

mhanifa:

The standard vertex form

Vermillions:

@mhanifa wrote:
The standard vertex form
y=a(x-h)2+k

mhanifa:

Good, now you need to determine the vertex on the graph, can you do that?

Vermillions:

@mhanifa wrote:
Good, now you need to determine the vertex on the graph, can you do that?
yes I can

mhanifa:

Please show

Vermillions:

@mhanifa wrote:
Please show
So the Vertex is 4?

mhanifa:

4 is one of the coordinates, the y, what about the x-coordinate of same point?

mhanifa:

Imagine a vertical line from that point, what would be the intersection point with x-axis?

Vermillions:

@mhanifa wrote:
4 is one of the coordinates, the y, what about the x-coordinate of same point?
2,4

mhanifa:

Excellent, you have (h, k) = (2, 4)

mhanifa:

Now, what would be the leading coefficient a? Is it positive or negative?

Vermillions:

Positive?

mhanifa:

Look at the graph, if the graph is U-shaped, then a would be positive, otherwise its negative.

Vermillions:

oooh okay

mhanifa:

So, what it your answer choice, after you determined that, a = -1, h = 2, k = 4?

Vermillions:

y=-(x+2)^2+4

mhanifa:

Substitute the values into vertex form you gave above

Vermillions:

y=-(x-2)4=x?

Vermillions:

or um y=-(x-2)2^+4

mhanifa:

Congrats, its correct

Vermillions:

omg thank you

mhanifa:

You are welcome! Hope you can solve similar problems yourself

Vermillions:

Thank you =]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!