how do i do this correctly my profesor sed im missing sum steps and why i changed the 2 to a 1 i had help from a previus person but i dont know what i did wron 2*│x-4│=2 2*│x-4│=1 2*│x-4│=-1 2x=1+4 2x=-1+4 x=5/2 x=3/2
Is the original equation 2|x - 4| = 2?
If so the first step is to divide both sides by 2.
yes 2|x - 4| = 2 is the first one
Can you do the first step?
do i devide |x - 4| by 2?
divide 2|x - 4| by 2, left side and divide 2 by 2, right side
What you get?
2/x-1/2=1
2|x - 4| / 2 = |x - 4| 2/2 = 1
i think i keep the | right?
You now have: |x - 4| = 1
i see
Can you continue from here?
Anything unclear at this step?
this is the next step right? │x-4│=1 │x-4│=-1
Right, its correct
But without absolute value symbols
x - 4 = 1 x - 4 = -1
Can you solve it from here?
i see ok ok
What is your solutions then?
x-4=1 x-4=-1 x=1+4 x=1+4 X=5/1 X=3/1
right?
Why you put x = 5/1, it should be x = 5, same with the other one. Otherwise all good, well done!
oh yah i grabd the 1 from the x basecly 1x but now that you day that yah it is done!
waw thx its correct
i can finally get my highschool degree after completing this last thing
Just to recap I'll add full solution here: 2|x - 4| = 2 |x - 4| = 1 x - 4 = 1 x - 4 = - 1 x = 1 + 4 x = -1 + 4 x = 5 x = 3 Thanks and good luck with your assignment!
u too have a nice day
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