When finding the real fourth roots for 256, which of the following would it be? -4 and 4 or 4 I know that a fourth root of 256 is 4, but does the rule of negative and positive roots work for this situation as well..
How would you find a square root for a start?
i think you misunderstood the question, I know the square root of 256 is 4, I just want to know how I would make sure that that is the ONLY real fourth root. maybe a method to check?
The square root of 256 is not 4, what is it?
We are coming to the point, but step by step
ok so would it be 16? i just thought i had to further simplify it.. is that correct?
and in addition to that, i dont need the square root, i need the fourth root, so wouldn't that be correct?
Is it only 16? Square of what else is 256?
ok so the square root of 256 is 16, and the square root of 16 is 4, correct?
Not only 16 and not only 4 ...
Remember this:\[\sqrt{x^2} = \pm x \]
So what do you get for the first square root and then for the second one?
i'm sorry, i had to step away. but back to the question, so it would be the square root of 256 is -16 and 16, and the following would be -4 and 4?
Yes, the real roots
You are welcome!
Join our real-time social learning platform and learn together with your friends!