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∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'. If vertex A is at (-1, 2) and vertex B is at (1, 5), then vertex A' is at and vertex B' is at .
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For each coordinate point, subtract 3 from the y coordinate and add 6 to the y coordinate \((x-3,y+6)\)
so for A' \((-1-3,2+6)\) and you can do the addition/subtraction B' \((1-3,5+6)\) and there isn't a 3rd coordinate i see
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