pre calculus help
Lmao
I think @extrinix can help u
If you’re using a calculator, this is easy to solve, to round it, round it to the nearest whole number (0). To truncate it, round it to the third decimal (0.000).
but how do I round 2/3
Round \(\dfrac{2}{3}\) to the nearest whole number, basically.
so 1?
Yes.
it says rounded to three decimals places and thats 1?
\(\frac{2}{3}=0.6\) (with a line on top of the 6) So if we're rounding to 3 decimal points we have to have _ . _ _ _ To round to the thousandths place we need the ten thousandths 0.6666 the last 6 is bigger than 5, so we have to round the thousandths place up one thousandths place + 1 = rounded thousandths place ->0.66 _ (6+1)
im not sure whats happenning
we have to round it to _ . _ _ _ (3 digits after the decimal point) or fraction is 2/3 which is 0.6666666666666666666, which we have to reduce to only 3 numbers do you get that?
so 06666.6
no we have 0.66666 continued on, but we have to have 3 digits after the decimal point
how do we get that
so, since we need to have 3 digits after the decimal point, we can first keep the first two, so we have 0.66 to determine the thousandths place, we have to look at the ten thousandths place. If the ten thousandths place number is smaller than 5, the thousandths place stays the same. But if the ten thousandths place is bigger than 5, we have to add one to the thousandths place. Because 6 is larger than 5, we have to add one more to the thousandths place 0.66 _ (6+1)
0.667?
yep
thats the answer?
that would be rounded to 3 decimal points, yes
wait
The given number truncated to three decimal places is
im not sure what truncated is
truncated is reduced, so what we did above is truncated to 3 decimal places
shortened maybe? so just 0.666
ok
it worked thanks
your welcome so apparently truncating is just reducing... but without the rounding part
*you're welcome the hell
Join our real-time social learning platform and learn together with your friends!