Ask your own question, for FREE!
Mathematics 14 Online
babyygurlllkellieee:

The image of a point is B'(-4, 11). A 180° clockwise rotation was performed to get this image. What were the coordinates of the pre-image? (-11, -4) (11, 4) (4, 11) (4, -11)

Extrinix:

Ok so, here’s how we’re going to look at the “graph”. Quadrant 2 (-x, y) - Quadrant 1 (x,y) Quadrant 3 (-x,-y) - Quadrant 4 (x,-y) Now, the coordinate provide is in Quadrant 2, so a 180 clockwise rotation to get here would make your pre-image (x,-y), which is Quadrant 4. So from this, your pre-image point would be (4,-11).

babyygurlllkellieee:

tysm! :)

Extrinix:

No problem!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!