The image of a point is C'(2, 7). A 90° clockwise rotation was performed to get this image. What were the coordinates of the pre-image?

(7, -2)
(-7, -2)
(-2, -7)
(-7, 2)

Question

The image of a point is C'(2, 7). A 90° clockwise rotation was performed to get this image. What were the coordinates of the pre-image?

(7, -2)
(-7, -2)
(-2, -7)
(-7, 2)

FexrlessRxby · Answer

I believe that the same process Extrinix showed in the previous question will correlate to this question too.

FexrlessRxby · Answer

"Ok so, here’s how we’re going to look at the “graph”.

Quadrant 2 (-x, y) - Quadrant 1 (x,y)
Quadrant 3 (-x,-y) - Quadrant 4 (x,-y)"

FexrlessRxby · Answer

From this, we know that the point is in the first quadrant.

FexrlessRxby · Answer

A 90 degree clockwise rotation would put it into the fourth quadrant, so the original point would be (7,-2).

babyygurlllkellieee · Answer

ohhhhh. tysm! :)

FexrlessRxby · Answer

Of course!