Question

Im so lost ;.;

Answer 1

do you know how to factor the function?

Answer 2

If im going to be honest no :/

Answer 3

ah, now that I think of it, it actually can't be factored

well, we can try to think of another distinctive feature - the y-intercept. what do you get when you plug in x = 0?

Answer 4

i dont know... but ive tried doing that in the past and its never worked ;.;

Answer 5

its -2 though.

Answer 6

y = -x^2 -4x - 2

notice what happens when we plug in x = 0

y = -0^2 - 4(0) - 2 = -2

so we know it crosses the y-axis at y = -2

Answer 7

now, that narrows us down to graphs 2 and 3 from the left, on the first row, since those are the only two that cross the y-axis at y = -2

how to distinguish them? well, since the x^2 term is negative, that means the parabola will look like the one on the right (https://amsi.org.au/ESA_Senior_Years/imageSenior/2a_5a.png)

therefore, the third option is your only possible choice

Answer 8

ohhhhhhh thats where i keep messing up. I kept thinking that (0,-2) would be where the vertex is.

Answer 9

thank you.