△ABC is dilated from the origin by scale factor r=1/4. Draw △A'B'C' and label the vertices with coordinates. the images triangle is A=(-10,6) B=(-11,2) C=(-4,4)
for each coordinate (x,y) multiply the x and y by 1/4 (x,y) -> (1/4 x , 1/4 y)
mhm
do you understand?
yes i understan that i have to do that but i forgiot hot to multiply it my 1/4
A = (-10,6) \( A=(-10 * \frac{1}{4} , 6 * \frac{1}{4}) = (\frac{-10}{4},\frac{6}{4})\) divide numerator and denominator by 2 \[(\frac{-5}{2},\frac{3}{2})\]
do the same with the other coordinates
oh ok thank you so much^_^
yw~
^_^^-^ thank you I really appreciate it
sorry to disturb so i divide everything by 2 or are each of them different
B = (-11, 2), scale factor of 1/4 (x,y) -> (1/4 x , 1/4 y) so (1/4 * -11, 1/4 * 2) = (-11/4 , 2/4) can you simplify the x or the y value?
that is what i am confused about I dont know how to do that
I was thinking -7,2 but i dont know if it is right
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