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Mathematics 16 Online
iSuckAtMath101:

Help? The diagram below models the layout at a carnival where G, R, P, C, B, and E are various locations on the grounds. GRPC is a parallelogram. Parallelogram GRPC with point B between C and P forming triangle GCB where GC equals 375 ft, CB equals 325 ft, and GB equals 425 ft, point E is outside parallelogram and segments BE and PE form triangle BPE where BP equals 225 ft. Part A: Identify a pair of similar triangles. (2 points) Part B: Explain how you know the triangles from Part A are similar. (4 points) Part C: Find the distance from B to E and from P to E. Show your work. (4 points)

iSuckAtMath101:

@carmelle are you busy or can you help with one more?

iSuckAtMath101:

ILikeToEatChildren:

A: PEB, GCB B: they both have 3 sides, they bother have the angle B I am not sure for question C

iSuckAtMath101:

are you sure those are right?

ILikeToEatChildren:

maybe, i can't check my own work

iSuckAtMath101:

lol alright

iSuckAtMath101:

@carmelle

ILikeToEatChildren:

might want someone else's opinion

carmelle:

Politely disagree with part A @iliketoeatchildren P is not a similar triangle to G Let's try using the triangle BGC instead, which triangle is similar (they have to be in the correct order as well) @isuckatmath101

iSuckAtMath101:

okay

iSuckAtMath101:

pbe or peb, im not good at orders

carmelle:

BEP actually I think that you should draw out the triangles like last time to help you. I'll do it for you :) For part B, we need to show how they are similar, are you familiar with the SSS theorem? |dw:1639522881805:dw|

iSuckAtMath101:

side side side

carmelle:

yup, what does it mean?

iSuckAtMath101:

when 3 sides are congruent then the triangles are congruent

carmelle:

yes 👏 now, can you find the sides? the picture should help ;o

iSuckAtMath101:

BG - BE, BC - BP, GC - EP

carmelle:

great :D Now for part C, we will set up two proportions... do you have an idea of what they will look like or would you like me to walk you through it as well?

iSuckAtMath101:

walk through? like last time

carmelle:

ok, so for this one, we know a lot of values so it will be easier... Lets start with BE: \[\frac{ BE }{ BG } = \frac{ PB }{ BC }\] Can you plug in the values and solve them?

iSuckAtMath101:

x/425 = 225/325

iSuckAtMath101:

x/425 = .6923076923

iSuckAtMath101:

idk what to do now...

carmelle:

wait no... you had it.. you just have to solve for x, x/425 = 225/325

carmelle:

remember, to cross multiply

iSuckAtMath101:

so i can cross multiply 425 with .6923076923?

carmelle:

not quite... does setting up the equation like this help? \[\frac{ x }{ 425 } =\frac{ 225 }{ 325 }\]

iSuckAtMath101:

325x = 95625

iSuckAtMath101:

so now what?

iSuckAtMath101:

divide by 325 on both sides?

carmelle:

yea, so now solve for x by dividing both sides by 325, you will get a fraction btw

iSuckAtMath101:

294.230769231

iSuckAtMath101:

i got decimal, cs im using a calculator

carmelle:

oh... just use an online calculator because working with decimals is hard lol

iSuckAtMath101:

i cant find a calculator online

iSuckAtMath101:

for this kind of fraction

carmelle:

try mathpapa.com

iSuckAtMath101:

x= 3825/13?

carmelle:

yup, so you can say BC = 3825/13 or294 3/13 both can work ^^^ Now to find PE, you will do \[\frac{ PB }{ BC } = \frac{ PE }{ BG }\] you can solve from there, right?

iSuckAtMath101:

idk yet

iSuckAtMath101:

x = 3825/13

iSuckAtMath101:

its the same thing...

iSuckAtMath101:

there is no way

iSuckAtMath101:

BE looks longer

iSuckAtMath101:

you there?

iSuckAtMath101:

@carmelle

carmelle:

wait... hold on one sec, lemme recheck, i think i might have done the proportion wrong, im sorry

iSuckAtMath101:

its okay

carmelle:

yea, i just rechecked, and i made a mistake, im so sorry. it should be: \[\frac{ PE }{ GC }=\frac{ BP }{ BC }\]

iSuckAtMath101:

3375/13?

carmelle:

yep, thats correct. PE = 3375/13

iSuckAtMath101:

can you convert that

iSuckAtMath101:

its not letting me

carmelle:

oh sure, that would be 259 8/13

iSuckAtMath101:

ty sm

iSuckAtMath101:

you were a very big help today

carmelle:

np and thank you for catching my mistake, i appreciate it :)

carmelle:

@isuckatmath101 wrote:
you were a very big help today
my pleasure (;

iSuckAtMath101:

:)

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