Question

math

Answer 1

do you understand how I would get
\[103 = (x+6)(3x-2) ~-(x-1)(2x)\]

Answer 2

Yes

Answer 3

great now can you factor it out, and put it all to one expression?

Answer 4

\[103=3x^2-12\] is that right?

Answer 5

for the first part?

Answer 6

no,
\[(a+b)(c+d) = ac+ad+bc+bd\]

Answer 7

\[103 = (x+6)(3x-2) ~-(x-1)(2x)\\103= 3x^2-2x+18x-12-(2x^2-2x)\\103 = 3x^2+16x-12-2x^2+2x\\103=x^2+18x-12\\0=x^2+18x-115\]

Answer 8

how come the 2x^2 is x^2?

Answer 9

3x^2 - 2x^2

Answer 10

oh okay

Answer 11

yes