Question

I am absolutely stuck on this:
It's Geometry, you have to write the equation in standard form (x-h)^2+(y-k)^2=r^2

Answer 1

So you have to use the center (-3,-2) and the point on the circle (5,7)

Answer 2

radius=point on the circle-center of the circle.
\[r=\sqrt{(5+3)^2+(7+2)^2}=\sqrt{64+81}=\sqrt{145}\]
(h,k)=(-3,-2)
h=-3
k=-2
eq. of circle is
\[(x+3)^2+(y+2)^2=(\sqrt{145})^2\]
\[x^2+6x+9+y^2+4y+4=145\]
simplify and write in the form\[x^2+y^2+2gx+2fy+c=0\]