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if log10 2 = a, log10 3 = 2b find the value of log3 12 help me pls :D
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\[\log_{10} 2=a \log_{10} 3=2b\] \[\log_{3}12 =\frac{ \log_{10}12 }{ \log_{10}3 }\] \[=\frac{ 2\log_{10}2+\log_{10} 3 }{ \log_{10}3 }\]
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