Mathematics
sophea:

if log10 2 = a, log10 3 = 2b find the value of log3 12 help me pls :D

sophea:

sophea:

$\log_{10} 2=a \log_{10} 3=2b$ $\log_{3}12 =\frac{ \log_{10}12 }{ \log_{10}3 }$ $=\frac{ 2\log_{10}2+\log_{10} 3 }{ \log_{10}3 }$