∠A and \angle B∠B are complementary angles. If m\angle A=(x-15)^{\circ}∠A=(x−15) ∘ and m\angle B=(3x-19)^{\circ}∠B=(3x−19) ∘ , then find the measure of \angle A∠A. plz help me i rlly need help!!!!
Well first you must find out what is x
i tried and i keep getting like 20 and 18, but they're wrong-
howd you get 20 and 18
by doing diff formulas and saying they equal 180 and the other equals 90 degrees-
Ok i think i found out what you did wrong
you dont Ill give you the formula and you find the answer ok?
4x-34=90 is the formula you solve
4x=124?
Yea and then divide
31
Try that
no-
IHHH OKK I GET IT NOW MBBB erase everything i said
okiii
Do 3x-19=90 since your looking for A you gotta find B
round it up so it would be 36
90-36= ?
54
\[\angle A+\angle B=90\] x-15+3x-19=90 4x-34=90 4x=90+34=124 x=124/4=31 \[\angle A=x-15=31-15=16\]
thx ^^
∠A and \angle B∠B are vertical angles. If m\angle A=(6x-26)^{\circ}∠A=(6x−26) ∘ and m\angle B=(5x+6)^{\circ}∠B=(5x+6) ∘ , then find the measure of \angle B∠B.
no- it said it was wrong-
send screenshot
@lura
do line b equals 180
and then 180 minus your answer
and that should give u line a
bruh istf delta mathhhhh is so dumb it said not correct
6x-26=5x+6 6x-5x=6+26 x=32 \[\angle B=5x+6=5\times 32+6=166\]
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