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plz help Solve this equation x²-14x+35=-10
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Quadratic Formula or Factoring?
quardiac
I'm new to this and i don't understand it at all
ya i need to solve quadratic by factoring
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so like a first step add to both sides 10 ,look what will get ...
@notleiland wrote:
You have to set the equation equal to zero, so \[x^{2}-14x+45\] and use the quadratic formula to solve
The quadratic formula is \[-b \pm \sqrt{b ^{2}}-4ac \div 2a\] the b in this case is 14, the a is 1, the c is 45 Plugging these in your equation would be \[-14 \pm \sqrt{14^{2}} - 4(1)(45) \div 2(1)\]
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the -4(1)(45) is supposed to be under the radical
Hope that helps :)
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