Ahmed wishes to buy upto 20 notebooks for his shop. he can buy either type A for $1.50 each or type B for $3. each he has a total of $45 he can spend. he must have at least 6 of each type in stock
Hello @aminkhan I am going to try and walk you through this. If at any point you are lost please tell me
First let's gather our information. He has a total of $45 to spend. Type A note books all cost 1.50 If we divide 45 by 1.50 we will have 30 note books. Type b not books are 3 dollars each. If we divide 45 by 3 we will be able to buy 15 note books.
Now. If we need a minimum of 6 note books for each I think the easiest way would be to multiply the cost by 6. So type A it would cost 9 dollars for 6 notebooks For type B it would cost 18 dollars for 6 notbookes
9+18=27
So we have already lost 27 dollars from our original 45 right?
Let's subraxt that 27 now
We have 18 dollars left to spend.
We have what, 12 notebooks already, and 18 dollars left. So I would go with the cheaper option which would be type A note books. If we divide 18 by 1.50 we would get 12 books. We don't want to go over 20 notebooks.
If we divide 18 by 3(remaining money divided by cost of Type B notebooks) we would get 6 notbooks
So from here I am thinking we buy the bare minimum and work our way up
If we buy 2 TA(type A notebooks) and 2 TB(type B notebooks) we will have we will have 9 dollars left.
Now since we just bought 4 new note books our notebook total have gone from 12, up to 16
So if we buy ten of each note books we would have 10 type A notebooks 10 type B notebooks And 0 dollars left over
Is that what the question was asking?
@thisgirlpretty is that right?!?
first we need to make inequalities please make inequalities first then solve
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