Help π§πΎββοΈ
are you fr rn
or am I dumb
Am I not allowed to say answers again?
How I ended up solving this was using PEMDAS. P β’ Parentheses β’ Example: (4+4) E β’ Exponents β’ Example: 8βΆ M β’ Multiplication β’ 4x4 D β’ Division β’ 8Γ·6 A β’ Addition β’ 7+9 S β’ Subtraction β’ 8-9 γ + (β³+ β’)=13 (β³+ β’)=8 γ+β³=7 If γ+(β³+ β’)=13 and we begin doing our parentheses, weβd start out given our first hint of (β³+ β’)=8. Continuing on, weβll take clues of γ+(β³+ β’)=13 and (β³+ β’)=8; or easier as 13-8= which is 13-8=5 letting us know γ=5. If we carry this method on with the rest of our problems of γ+β³=7, we know know γ=5, leaving us with β³=2. So therefore, 5+2=7. Then our triangle which is 2+β’= knowing weβve figured out the rest of our problem, itβd be 6. Therefore, γ=5 β³=2 β’=6 In order to make sure our choices are correct from our first provided hint which is γ + (β³+ β’)=13 weβll solve it from our number choices. 5+(2+6) =5+(8) =5+8 =13
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