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Mathematics 13 Online
martai:

Help πŸ§πŸΎβ€β™‚οΈ

martai:

1 attachment
PureSoulless:

are you fr rn

PureSoulless:

or am I dumb

PureSoulless:

Am I not allowed to say answers again?

umm:

How I ended up solving this was using PEMDAS. P β€’ Parentheses β€’ Example: (4+4) E β€’ Exponents β€’ Example: 8⁢ M β€’ Multiplication β€’ 4x4 D β€’ Division β€’ 8Γ·6 A β€’ Addition β€’ 7+9 S β€’ Subtraction β€’ 8-9 〇 + (β–³+ β–’)=13 (β–³+ β–’)=8 〇+β–³=7 If 〇+(β–³+ β–’)=13 and we begin doing our parentheses, we’d start out given our first hint of (β–³+ β–’)=8. Continuing on, we’ll take clues of 〇+(β–³+ β–’)=13 and (β–³+ β–’)=8; or easier as 13-8= which is 13-8=5 letting us know 〇=5. If we carry this method on with the rest of our problems of 〇+β–³=7, we know know 〇=5, leaving us with β–³=2. So therefore, 5+2=7. Then our triangle which is 2+β–’= knowing we’ve figured out the rest of our problem, it’d be 6. Therefore, 〇=5 β–³=2 β–’=6 In order to make sure our choices are correct from our first provided hint which is 〇 + (β–³+ β–’)=13 we’ll solve it from our number choices. 5+(2+6) =5+(8) =5+8 =13

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