Math help?

Question

Math help?

Lazorwolf64 · Answer

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gcc8617 · Answer

Uhm it's either 6x-7x=12 which be 6x-7x=-1x then divide -1 by -1x and 12 and you should get x=-12 or it would be 9x-7x which equals 2x then divide 2 by 2x and 12 and you should get x=6

gcc8617 · Answer

Hold on let me check

gcc8617 · Answer

Okay so it's the second one. It's 9x-7x=12 so 9x-7x=2x then 2x is divided by 2 cross the twos out and divide 2 by 12 and you should get x= 6

Luigi0210 · Answer

Looks like you might need to use the quadratic formula:

$$\Large x= \frac{-b \pm \sqrt{b^2-4ac~}}{2a} $$

where a, b, and c are constants associated with your polynomial
$\large 3x^2-7x-12=0$ so a= 3, b = -7 and c = -12
$$\Large x= \frac{-(-7) \pm \sqrt{(-7)^2 - 4 (3)(-12)~}}{2(3)} $$

jhonyy9 · Answer

@luigi0210 wrote:

Looks like you might need to use the quadratic formula: $$\Large x= \frac{-b \pm \sqrt{b^2-4ac~}}{2a} $$ where a, b, and c are constants associated with your polynomial $\large 3x^2-7x-12=0$ so a= 3, b = -7 and c = -12 $$\Large x= \frac{-(-7) \pm \sqrt{(-7)^2 - 4 (3)(-12)~}}{2(3)} $$

explained very nice ,so just a little ATTENTION please ,because in the formula there are + and - signs between -b and square root so this mean that will result two roots so in this way please write x_1,2 = ... thank you in advance

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