Question

help please... i did some of the work, but I'm stuck

Answer 1

idk how to do math

Answer 2

I can not read it

Answer 3

\[10C9 (.8)^{9}(.4)^{1} + 10C10 (.8)^{10}(.2)^{2}\]

The 10C9 is 10 choose 9
And the same for 10C10 but 10 choose 10

Answer 4

That's what I need help with

Answer 5

ask a teacher

Answer 6

Let's see what I can do dad

Answer 7

Let's go over what "10 choose 9" and "10 choose 10" mean These are combinations, which are a way of selecting items from a group, where the order doesn't really matter the number of combinations of selecting "r" items from "n" items is given by

Answer 8

Yeah, I know that. And actually I'm going to do this one my own. I think I know how I can solve this now

Answer 9

Where n! (n factorial) is the product of all positive integers up to/ until n
So for our first step, we'll need to calculate 10 choose 9 (10C9)
This means we are choosing 9 items from a group of 10. The formula will be: