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The Pythagorean theorem: \(a^2+b^2=c^2\). \(a=90\text{ft}\), \(b=90\text{ft}\). Solve for \(c\).
@wio wrote:
The Pythagorean theorem: \(a^2+b^2=c^2\).
\(a=90\text{ft}\), \(b=90\text{ft}\).
Solve for \(c\).
Another trick here: it's on the \(x\) axis. It goes from slightly above 60 to slightly below -60. \(60 - (-60) = 120\). So our answer is approximately 120.
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@wio wrote:
Another trick here: it's on the \(x\) axis. It goes from slightly above 60 to slightly below -60.
\(60 - (-60) = 120\).
So our answer is approximately 120.
Yeah, I said it is approximate, not exact. If it is approximate than the correct answer will be nearest to it. Again, look at the diagram.
Which of the answers looks closest to 120?
I got it from here thanks
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