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Mathematics 35 Online
Breathless:

WOmp

Breathless:

1 attachment
idontexistrn1:

ewwwwwwwwww

adrianluvvsyouu2:

Do you need help solving it?

Breathless:

yes

adrianluvvsyouu2:

Use like terms, when you have 2z and another 2z for instance, you can add those to 4z. Same idea with 5z^2 - 3z^2, the z^2 is the same so you can add their coefficient (the number in front of the variable). -2z^2 - 15z - 9 - 11z^2 - 8z + 2 Its easy when its addition of polynomials, its harder when subtracting (since you have to multiply everything in parenthesis by -1)

adrianluvvsyouu2:

Using those examples I think you can simplify the expression

Breathless:

thx!

adrianluvvsyouu2:

You should have gotten -13z^2 - 23z - 7 or -(13z^2 + 23z + 7)

idontexistrn1:

@adrianluvvsyouu2 wrote:
You should have gotten -13z^2 - 23z - 7 or -(13z^2 + 23z + 7)
smartyyy

sllo:

U have reddit, u have chat gpt

Breathless:

leave him be --v

Breathless:

@adrianluvvsyouu2 wrote:
You should have gotten -13z^2 - 23z - 7 or -(13z^2 + 23z + 7)
yup!

adrianluvvsyouu2:

@idontexistrn1 wrote:
@adrianluvvsyouu2 wrote:
You should have gotten -13z^2 - 23z - 7 or -(13z^2 + 23z + 7)
smartyyy
I'm taking calculus now, you have to know this stuff by heart

adrianluvvsyouu2:

@breathless wrote:
@adrianluvvsyouu2 wrote:
You should have gotten -13z^2 - 23z - 7 or -(13z^2 + 23z + 7)
yup!
Good job then!

Breathless:

;p

Breathless:

thank you for helping

adrianluvvsyouu2:

No problem, you can @ me for any subject except maybe world history, I'm a bit rusty

Breathless:

oki doki

Joyandy:

wild

Breathless:

@joyandy wrote:
wild
eh

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