Solve given system

4x-5y=40
x=3y+24

Question

Solve given system

4x-5y=40
  x=3y+24

Makala2fine · Answer

@xxaikoxx

Luigi0210 · Answer

One way you could do it is by substitution. Subbing in $\color{red}{x}=3y+24$  for $ 4\color{red}{x} -5y=40 $

Giving you something like this:

$\large 4(3y+24)-5y =40 $

Solve for y:

$\large 12y+96-5y=40 $

$\large 7y=56 $

$\large y= 8$

Now that you have $\large \color{gold}{y}$, you can plug that back in and solve for $\large \color{red}{x}$.

gdubb08 · Answer

The only thing I got outta this is when I looked at x, I wondered y.

Makala2fine · Answer

@luigi0210 wrote:

One way you could do it is by substitution. Subbing in $\color{red}{x}=3y+24$ for $ 4\color{red}{x} -5y=40 $ Giving you something like this: $\large 4(3y+24)-5y =40 $ Solve for y: $\large 12y+96-5y=40 $ $\large 7y=56 $ $\large y= 8$ Now that you have $\large \color{gold}{y}$, you can plug that back in and solve for $\large \color{red}{x}$.

Thank you

surjithayer · Answer

4x-5y=40
x=3y+24
4(3y+24)-5y=40
12y+96-5y=40
7y=40-96
7y=-56
y=-56/7=-8
x=3(-8)+24
x=-24+24
x=0
x=0,y=-8