Question

chem

Answer 1

am i right with C here?

Answer 2

last one btw

Answer 3

@sllo can u help

Answer 4

The reaction is:

2 H2 + O2 → 2 H2O

We can use the following steps to solve the problem:

1. Convert grams of reactants to moles:
- Moles of H2 = 11 g / 2.016 g/mol = 5.46 mol
- Moles of O2 = 45 g / 32 g/mol = 1.41 mol

2. Determine the limiting reactant:
- The mole ratio of H2 to O2 is 2:1.
- For every 1 mole of O2, we need 2 moles of H2.
- Since we have 1.41 moles of O2, we would need 2.82 moles of H2.
- We only have 5.46 moles of H2, so H2 is in excess and O2 is the limiting reactant.

3. Calculate the theoretical yield of H2O:
- The mole ratio of O2 to H2O is 1:2.
- Since we have 1.41 moles of O2, we can produce 2.82 moles of H2O.
- Mass of H2O = 2.82 mol * 18.015 g/mol = 50.8 g

This means that the correct answer is: 45 g O2 is the limiting reactant; theoretical yield is 51 grams H2O.