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Mathematics 7 Online
gdubb08:

Math help:

gdubb08:

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gdubb08:

And don't take this post down, I'm tryna get help here and ya'll keep taking it down, then banning me

gdubb08:

Shadow you don't need to write a whole essay lol. THE ANTICIPATION IS KILLING MEEEE!!!

gdubb08:

ima eat a sandwhich. I'll be back

sllo:

First, simplify the coes 12/21 = 2/3 then cancel out x ^8 and subtract the exponents of y: y ^6-2= y=^4 giving the final answer 2y^4/3

sllo:

First simplify the coes 14/21* Mb

gdubb08:

@sllo wrote:
First, simplify the coes 12/21 = 2/3 then cancel out x ^8 and subtract the exponents of y: y ^6-2= y=^4 giving the final answer 2y^4/3
I trust shadow more. Sorry

sllo:

@gdubb08 wrote:
@sllo wrote:
First, simplify the coes 12/21 = 2/3 then cancel out x ^8 and subtract the exponents of y: y ^6-2= y=^4 giving the final answer 2y^4/3
I trust shadow more. Sorry
We literally got the same answer

gdubb08:

@sllo wrote:
@gdubb08 wrote:
@sllo wrote:
First, simplify the coes 12/21 = 2/3 then cancel out x ^8 and subtract the exponents of y: y ^6-2= y=^4 giving the final answer 2y^4/3
I trust shadow more. Sorry
We literally got the same answer
cool

Shadow:

Yeah that's what I got as well. I used the wrong coefficients at the start, silly me (: But let me know if you don't understand how you get there.

gdubb08:

@shadow wrote:
Yeah that's what I got as well. I used the wrong coefficients at the start, silly me (: But let me know if you don't understand how you get there.
so for \[5x^1y^1/5x^2y^8\] , would you get 1/1*1/x\[^1\]*1/y^7? Then 3/1x^1y^7?

Shadow:

\[\frac{ 3 }{ x y^8}\] so ur saying that's the end result, for that new expression?

gdubb08:

@shadow wrote:
\[\frac{ 3 }{ x y^8}\] so ur saying that's the end result, for that new expression?
I forgot. I'm on a new problem now. Here:

gdubb08:

\[9x^5y^8/3x^1y^1\] I got \[3x^4y^7\]

Shadow:

yup that's correct.

gdubb08:

@shadow wrote:
yup that's correct.
now more math -_-

gdubb08:

@shadow wrote:
yup that's correct.
everytime I look at x, I wonder y

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