Question

need some algebra help

Answer 1

x = ln(5/8)
x = ln(5) - ln(8)

Answer 2

do you know how to put it into log form? i would first put this in exponent form and work through trying to get x alone.

Answer 3

\[\log_{\frac{ 1 }{ 4}}32 = x+1\]

Answer 4

I will continue this TOMMOROW do not close this mods

Answer 5

\[(\frac{ 1 }{ 4 })^{x+1}=32\]
\[\left( \frac{ 1 }{ 2^2 } \right)^{x+1}=2^{5}\]
\[\left( 1\times2^{-2} \right)^{x+1}=2^{5}\]
\[\left( 2 \right)^{-2(x+1)}=2^{5}\]
-2(x+1)=5
-2x-2=5
-2x=5+2
-2x=7
\[x=-\frac{ 7 }{ 2 }\]

Answer 6

crumb crumingtion never did his so called "continuing" on this question ;-;