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Mathematics 43 Online
CrumbCrumbington:

need some algebra help

CrumbCrumbington:

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SaltySuga:

x = ln(5/8) x = ln(5) - ln(8)

CrumbCrumbington:

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bubbly1belle:

do you know how to put it into log form? i would first put this in exponent form and work through trying to get x alone.

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bubbly1belle:

\[\log_{\frac{ 1 }{ 4}}32 = x+1\]

CrumbCrumbington:

I will continue this TOMMOROW do not close this mods

ykbatman:

@saltysuga wrote:
x = ln(5/8) x = ln(5) - ln(8)
In stead of giving him the answer straight away, try leading him towards the answer step by step.

SaltySuga:

@ykbatman wrote:
@saltysuga wrote:
x = ln(5/8) x = ln(5) - ln(8)
In stead of giving him the answer straight away, try leading him towards the answer step by step.
Alright boss

surjit:

\[(\frac{ 1 }{ 4 })^{x+1}=32\] \[\left( \frac{ 1 }{ 2^2 } \right)^{x+1}=2^{5}\] \[\left( 1\times2^{-2} \right)^{x+1}=2^{5}\] \[\left( 2 \right)^{-2(x+1)}=2^{5}\] -2(x+1)=5 -2x-2=5 -2x=5+2 -2x=7 \[x=-\frac{ 7 }{ 2 }\]

KingVasquez:

crumb crumingtion never did his so called "continuing" on this question ;-;

CrumbCrumbington:

@ykbatman wrote:
@saltysuga wrote:
x = ln(5/8) x = ln(5) - ln(8)
In stead of giving him the answer straight away, try leading him towards the answer step by step.
Don't start this bs, I need actual answers I'm not even taking this class next year

adrianluvvsyouu2:

@crumbcrumbington wrote:
@ykbatman wrote:
@saltysuga wrote:
x = ln(5/8) x = ln(5) - ln(8)
In stead of giving him the answer straight away, try leading him towards the answer step by step.
Don't start this bs, I need actual answers I'm not even taking this class next year
"This bs" you are referring to is in the rules of questioncove. I don't understand this mentality at all. When you take later math you will need to understand logarithms again, but you will have forgotten all of it. Instead of begging us for the answers and being rude to users, allow yourself to be taught the subject, so you can succeed on your tests and later math classes.

CrumbCrumbington:

@adrianluvvsyouu2 wrote:
@crumbcrumbington wrote:
@ykbatman wrote:
@saltysuga wrote:
x = ln(5/8) x = ln(5) - ln(8)
In stead of giving him the answer straight away, try leading him towards the answer step by step.
Don't start this bs, I need actual answers I'm not even taking this class next year
"This bs" you are referring to is in the rules of questioncove. I don't understand this mentality at all. When you take later math you will need to understand logarithms again, but you will have forgotten all of it. Instead of begging us for the answers and being rude to users, allow yourself to be taught the subject, so you can succeed on your tests and later math classes.
I'm never using this in my life outside of high school, I just need this for a credit, idec dude I don't even take algebra exams

SaltySuga:

@adrianluvvsyouu2 wrote:
@crumbcrumbington wrote:
@ykbatman wrote:
@saltysuga wrote:
x = ln(5/8) x = ln(5) - ln(8)
In stead of giving him the answer straight away, try leading him towards the answer step by step.
Don't start this bs, I need actual answers I'm not even taking this class next year
"This bs" you are referring to is in the rules of questioncove. I don't understand this mentality at all. When you take later math you will need to understand logarithms again, but you will have forgotten all of it. Instead of begging us for the answers and being rude to users, allow yourself to be taught the subject, so you can succeed on your tests and later math classes.
Omds

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