Okay so I figured out D1 already and D2 but idk anything about D3
gelphielvr:
Okay nevermind - D2 is not solved yet. if anyone knows the answer pls just tell me
I don't even need the solving way
Luigi0210:
I'm going to assume it's the general steps for all 3 problems, so here they are:
\(\large 1\). Assume 100 g of substance
\(\large 2 \). Convert everything to moles
\(\large 3\). Divide by the smallest ratio.
\(\large 4\). Clear any fractions to whole numbers
If you want, I can show ya on Substance 3?
gelphielvr:
for D2 I have
15.87g = 1.3213mol C
2.22g = 2.1980mol H
18.15g = 1.2955mol N
63.41g = 3.9631mol O
I just don't know how to divide it correctly and how to round
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gelphielvr:
@gelphielvr wrote:
for D2 I have
15.87g = 1.3213mol C
2.22g = 2.1980mol H
18.15g = 1.2955mol N
63.41g = 3.9631mol O
I just don't know how to divide it correctly and how to round
like I know I have to divide it by the smallest number but I don't know how to round it correctly
Luigi0210:
I would suggest (unless your teacher specifically says), only use 2 significant figures, it makes things easier, so:
C: 1.32 moles
H: 2.20 moles
N: 1.30 moles
O: 3.96 moles
But now, just divide it by the smallest number, which would be 1.30
C: ~ 1.02
H: ~ 1.69
N: ~ 1.00
O: ~ 3.05
Now to get whole numbers, just multiply it by 3:
C: ~ 3
H: ~ 5
N: ~ 3
O: ~ 9
So formula:
\(\Large C_3 H_5 N_3 O_9 \)
If I did it correctly ofc lol
gelphielvr:
@luigi0210 wrote:
I would suggest (unless your teacher specifically says), only use 2 significant figures, it makes things easier, so:
C: 1.32 moles
H: 2.20 moles
N: 1.30 moles
O: 3.96 moles
But now, just divide it by the smallest number, which would be 1.30
C: ~ 1.02
H: ~ 1.69
N: ~ 1.00
O: ~ 3.05
Now to get whole numbers, just multiply it by 3:
C: ~ 3
H: ~ 5
N: ~ 3
O: ~ 9
So formula:
\(\Large C_3 H_5 N_3 O_9 \)
If I did it correctly ofc lol
unfortunately our teacher told us to use thousands (idk why)
but yes this is correct!! thank you so so much I really appreciate it