Question

need to prove identities sin^2thetacos^2theta=1\8[1-cos(4theta)]

Answer 1

LHS = (sin^2theta)(cos^2theta)
= 0.5(1-cos2theta)(0.5)(cos2theta+1)
= 0.25(1-cos^2 2theta)
= 0.25(1-0.5(cos4theta+1))
= 1/8(1-cos4theta)
= RHS
please represent your answer in consistency when using fractions and decimals : )