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Mathematics 69 Online
OpenStudy (anonymous):

Hey...can anyone please explain how I figure out if ~(p ^ q) is equivalent or not equivalent to ~p ^ q

OpenStudy (heisenberg):

I believe you can use a truth table to check this. Make a truth table for each and see if they are the same.

OpenStudy (anonymous):

It isn't the equivalence of ~(P ^ Q) would be ~P \/ ~Q according to DeMorgan's law.

OpenStudy (heisenberg):

does ^ = logical OR and \/ = logical AND?

OpenStudy (anonymous):

^ is and \/ is or

OpenStudy (anonymous):

^ is the "and" and V is the "or"

OpenStudy (anonymous):

I was thinking it was what zealhack was saying...but I always confuse myself!!

OpenStudy (heisenberg):

you can make a truth table. check each combination of true and false like this: p = true, q = true: ~(true ^ true) = ~(true) = false p = true, q = false: ~(true ^ false) = ~false = true and so forth. make sense?

OpenStudy (heisenberg):

there will be 4 rows for each table (TT, TF, FT, FF). if the two tables are identical then the statements are equivalent.

OpenStudy (anonymous):

right, this all makes sense

OpenStudy (anonymous):

so in the first column of answers it would end up being T, F, F, F...right?

OpenStudy (heisenberg):

for which statement?

OpenStudy (anonymous):

wouldn't that just mean the number has to be 5 or bigger?

OpenStudy (heisenberg):

there are no numbers per say. these are logical expressions. each p, q can only be either true or false.

OpenStudy (anonymous):

heisenberg...right, I was helping another girl (trying to) and it popped up on here...sorry about that. The statement I was figuring out was the first one: ~(p ^ q)

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