Question

find the limit. Lim x-->1....(2x^4-6x^3+x^2+3)/(x-1)

Answer 1

If you plug x=1 into your equation, you'll get 0/0. That means you can apply L'Hospital's rule (take the derivative of the numerator and denominator).
Applying L'Hospital's rule, you'll get \[\lim_{x \rightarrow 1} 8x^{3}-18x^{2}+2x\]
Now you can evaluate your limit.

Answer 2

thank you