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Mathematics 16 Online
OpenStudy (anonymous):

logarithms anyone?

OpenStudy (bahrom7893):

i gotta revise those too, so what are the questions?

OpenStudy (anonymous):

how do i get the inverse y=logsub3x

OpenStudy (anonymous):

so its y=(little3at the bottom)x

OpenStudy (bahrom7893):

k

OpenStudy (bahrom7893):

\[y=\log_{3}x \] \[3^{y}=x\] So x = y^3 is that what u mean by inverse?

OpenStudy (anonymous):

the inverse of the function

OpenStudy (anonymous):

i dont get that either

OpenStudy (bahrom7893):

http://www.andrews.edu/~calkins/math/webtexts/numb17.htm sorry havent done logs in a long time, i only use Ln,s but that is the inverse function

OpenStudy (bahrom7893):

inverse function is: Say: y = f(x) then inverse is: x = F^-1 (y), which basically means solve for X

OpenStudy (anonymous):

ok thank you soo much

OpenStudy (bahrom7893):

hey can u check the answer key.. like gimme any problem with an answer to it

OpenStudy (bahrom7893):

and ill make sure the answer's right

OpenStudy (anonymous):

answer key? like in the back of the book?

OpenStudy (anonymous):

ummm, this is a unit 4 test that was left for hw, so we cant look at the answers in the back of the book T_T

OpenStudy (bahrom7893):

just gimme any similar problems from the book that has an answer to it

OpenStudy (bahrom7893):

like anything like y = log(sub5)x and then it has an answer.. numbers dont matter

OpenStudy (anonymous):

ok, wait a sec

OpenStudy (anonymous):

13. y=logsubX

OpenStudy (anonymous):

answer: f^-19x0=7^x

OpenStudy (anonymous):

*answer: f^-1(x)=7^x

OpenStudy (bahrom7893):

u forgot to add what is under sub

OpenStudy (anonymous):

sorry the second is the real answer

OpenStudy (anonymous):

there is no under sub

OpenStudy (bahrom7893):

Oh its just \[y = \log_{} x\]

OpenStudy (bahrom7893):

?

OpenStudy (anonymous):

ya, its: y=log(undersub7) X

OpenStudy (anonymous):

answer:f^-1(x)=7^x

OpenStudy (bahrom7893):

Okay that makes sense now

OpenStudy (anonymous):

sorry if i confused you!

OpenStudy (bahrom7893):

So my answer wasn't technically wrong but still it was in wrong notation

OpenStudy (bahrom7893):

workin on the first one

OpenStudy (anonymous):

oh alright

OpenStudy (bahrom7893):

\[y=\log_{3}x ; x = 3^{y} ; f ^{-1} (x) = 3^{x}\]

OpenStudy (anonymous):

i understood everything till the last setp

OpenStudy (bahrom7893):

oh for you to make it into inverse, just replace y with x, say: Sin(x) = y; Sin^-1(y) = x

OpenStudy (anonymous):

so would i have to put it as : \[\prime-1(x)=3^{x}\]

OpenStudy (anonymous):

i meant f^-1(x)=3^x

OpenStudy (bahrom7893):

yes

OpenStudy (anonymous):

hmm, i was pretty sure you could have answered it differently. it cant be: y=3^x

OpenStudy (anonymous):

oh thanks that seems helpful, can i ask 1 more and see if i get it?

OpenStudy (bahrom7893):

yeah

OpenStudy (anonymous):

f(x)=lnx

OpenStudy (anonymous):

ok, i dont even know what to do here,

OpenStudy (anonymous):

we basically solve for x, right?

OpenStudy (bahrom7893):

yup and this is my favourite stuff! so useful in calculus

OpenStudy (bahrom7893):

k so Lnx is the same as Log(sub e)X, where e is approximately 2.71

OpenStudy (anonymous):

right

OpenStudy (anonymous):

oh,. sorry, how can i add you as a fan?

OpenStudy (anonymous):

oh, nvm, haha

OpenStudy (bahrom7893):

sure lol

OpenStudy (anonymous):

ok, so i get it so far

OpenStudy (bahrom7893):

good and start a new topic. this is getting annoying, my browser keeps scrollin up and down. this place is buggy

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