Mathematics
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OpenStudy (anonymous):
logarithms anyone?
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OpenStudy (bahrom7893):
i gotta revise those too, so what are the questions?
OpenStudy (anonymous):
how do i get the inverse y=logsub3x
OpenStudy (anonymous):
so its y=(little3at the bottom)x
OpenStudy (bahrom7893):
k
OpenStudy (bahrom7893):
\[y=\log_{3}x \]
\[3^{y}=x\]
So x = y^3 is that what u mean by inverse?
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OpenStudy (anonymous):
the inverse of the function
OpenStudy (anonymous):
i dont get that either
OpenStudy (bahrom7893):
inverse function is:
Say:
y = f(x)
then inverse is: x = F^-1 (y), which basically means solve for X
OpenStudy (anonymous):
ok thank you soo much
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OpenStudy (bahrom7893):
hey can u check the answer key.. like gimme any problem with an answer to it
OpenStudy (bahrom7893):
and ill make sure the answer's right
OpenStudy (anonymous):
answer key? like in the back of the book?
OpenStudy (anonymous):
ummm, this is a unit 4 test that was left for hw, so we cant look at the answers in the back of the book T_T
OpenStudy (bahrom7893):
just gimme any similar problems from the book that has an answer to it
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OpenStudy (bahrom7893):
like anything like y = log(sub5)x and then it has an answer.. numbers dont matter
OpenStudy (anonymous):
ok, wait a sec
OpenStudy (anonymous):
13. y=logsubX
OpenStudy (anonymous):
answer: f^-19x0=7^x
OpenStudy (anonymous):
*answer: f^-1(x)=7^x
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OpenStudy (bahrom7893):
u forgot to add what is under sub
OpenStudy (anonymous):
sorry the second is the real answer
OpenStudy (anonymous):
there is no under sub
OpenStudy (bahrom7893):
Oh its just \[y = \log_{} x\]
OpenStudy (bahrom7893):
?
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OpenStudy (anonymous):
ya, its: y=log(undersub7) X
OpenStudy (anonymous):
answer:f^-1(x)=7^x
OpenStudy (bahrom7893):
Okay that makes sense now
OpenStudy (anonymous):
sorry if i confused you!
OpenStudy (bahrom7893):
So my answer wasn't technically wrong but still it was in wrong notation
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OpenStudy (bahrom7893):
workin on the first one
OpenStudy (anonymous):
oh alright
OpenStudy (bahrom7893):
\[y=\log_{3}x ; x = 3^{y} ; f ^{-1} (x) = 3^{x}\]
OpenStudy (anonymous):
i understood everything till the last setp
OpenStudy (bahrom7893):
oh for you to make it into inverse, just replace y with x, say:
Sin(x) = y; Sin^-1(y) = x
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OpenStudy (anonymous):
so would i have to put it as :
\[\prime-1(x)=3^{x}\]
OpenStudy (anonymous):
i meant f^-1(x)=3^x
OpenStudy (bahrom7893):
yes
OpenStudy (anonymous):
hmm, i was pretty sure you could have answered it differently. it cant be:
y=3^x
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OpenStudy (anonymous):
oh thanks that seems helpful, can i ask 1 more and see if i get it?
OpenStudy (bahrom7893):
yeah
OpenStudy (anonymous):
f(x)=lnx
OpenStudy (anonymous):
ok, i dont even know what to do here,
OpenStudy (anonymous):
we basically solve for x, right?
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OpenStudy (bahrom7893):
yup and this is my favourite stuff!
so useful in calculus
OpenStudy (bahrom7893):
k so Lnx is the same as Log(sub e)X, where e is approximately 2.71
OpenStudy (anonymous):
right
OpenStudy (anonymous):
oh,. sorry, how can i add you as a fan?
OpenStudy (anonymous):
oh, nvm, haha
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OpenStudy (bahrom7893):
sure lol
OpenStudy (anonymous):
ok, so i get it so far
OpenStudy (bahrom7893):
good and start a new topic. this is getting annoying, my browser keeps scrollin up and down. this place is buggy