Question

implicit differentiation: sin((x^2)(y^2))=x

Answer 1

ok

Answer 2

is this sin [ x^2y^2] = x ?
or (sin x^2 ) y^2 = x

Answer 3

first one

Answer 4

ok

Answer 5

please make me fan

Answer 6

make you fan?

Answer 7

jkwon, let me answer it. i got this

Answer 8

\[\sin(x^2y^2)=x \]
\[\cos(x^2y^2)(2xy^2+x^2(2y)(y')=1\]
\[2xy^2+x^2(2y)y'=1/[\cos(x^2y^2)]\]

Answer 9

grrrr

Answer 10

oh ok

Answer 11

oh wow

Answer 12

how do you use latex?

Answer 13

Oh I only did half of it

Answer 14

could you explain chain rule?

Answer 15

sure

Answer 16

how do you type latex
like type integral x dx

Answer 17

So you treat the problem like an onion. You do the outer layer and then you go to the second layer, then the third. So the outer layer is the cosine, and the inner layer is the x^2y^2

Answer 18

So then....

Answer 19

Oops i mean sine is the outer layer

Answer 20

yeah i gotcha. so you just derive each in parts depending on parenthesis

Answer 21

pretty much yeah ^^

Answer 22

remember the inside is the product

Answer 23

haha, jk i think you have this in the bud

Answer 24

huh?

Answer 25

nvm

Answer 26

well im a math major, so whatever needs help, I like to solve it

Answer 27

whats a non archimedean ordered field?

Answer 28

can you ask that in a separate question? you're distracting him from helping me

Answer 29

so yeah, the product rule for the x^2y^2

Answer 30

yuppp

Answer 31

notgoodatmath, dont speak unless told to

Answer 32

i have 15 fans, i have solved a hundred math problems

Answer 33

what is Y'?

Answer 34

I just want help with this problem, and you aren't helping me. Your're doing the opposite actually.

Answer 35

hey cantorset, use the equation editor in the lower left hand side of the reply box

Answer 36

for latex

Answer 37

oh ok
did you see my comment on n^n / n!

Answer 38

oh did not check heh, will do so

Answer 39

i dont see that as an argument
what you did to show it converges