Question

integral of (x^2+5x+6)/(x^2+2x+1)
partial fraction form
please help!

Answer 1

ok so you see that the denominator is \[x^2+2x+1\]
So you should first factor the denominator. Then you get (x+1)^2

Then finally:

\[(x^2+5x+6)/(x+1)^2= A/(x+1) + B/(x+1)\]

\[\]
You you think you can do the rest?

Answer 2

\[A/(x+1)+B/(x+1)\]

Answer 3

oops...keeping doing typos

Answer 4

\[A/(x+1)+B(x+1)^2\]

Answer 5

how does it get from (x^2+5x+6)/(x^2+2x+1)
to
1+ (3x+5)/(x^2+2x+1)

Answer 6

thank you for your help btw

Answer 7

I didn't get 1+(3x+5).... Just factor the bottom and put the coefficients like i did above.