Question

what is the solution to the system of equations shown below?

2x-y+3z=8
x-6y-z=0
-6x+3y-9z=24

please someone help!

Answer 1

Set up a matrix:
2 -1 3 | 8
1 -6 -1 | 0
-6 3 -9 | 24
Bring it to reduced row echelon form (no nonzero terms except leading 1s)
You'll have x, y, z.

Answer 2

ugh im still confused lol, how would i set it up though?

Answer 3

Take the coefficients of each equation and put them in a matrix.
Then perform row operations (ex. \[R_3 \rightarrow R_2 - R_1\])

Answer 4

okay thank uu