Question

a tank shape cone with diameter 40ft and depth 20ft filled rate of 10cu ft/min how fast depth is changing when filled to depth of 10 ft

Answer 1

when is this due?

Answer 2

tuesday i know dont have any clue now looking at the book is not helping me notes and online :-(

Answer 3

hey i will solve this, but im helpin someone out right now, so if u want send me an email at bahrom.cfo@gmail.com and i will email u the solution as soon as im done with the other girl/guy

Answer 4

thank you so much ;=)

Answer 5

np.. i might even answer here as soon as im done with that other person

Answer 6

ok if not i will send you and email i still have time for tutoring thank you ;-)

Answer 7

So:
You are given:
r = 20 ft (diameter is 40ft, radius is half of 40 = 20ft)
h = 20 ft
dV/dt = + 10ft^3/min (change in volume is positive as it is being filled up)

Answer 8

now when depth or h is 10, what is dh/dt (change in depth)

Answer 9

So let me rewrite this neatly:
r = 20ft
h = 20 ft
dV/dt = 10 ft^3/min
dh/dt at h = 10 is ?

Answer 10

hey i have to graph some stuff for this, can u go here:
http://www.twiddla.com/496286

Answer 11

click on that link, i still don't see u there

Answer 12

u here?

Answer 13

dont see anything on the white board

Answer 14

thankkkkkkkk youuuuuuuuuuuuuuuuuuuuuuuu for the help

Answer 15

You are veryyyy welcome!!!