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squarre root of 2x+16- square root of x =4
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did u mean: \[\sqrt{2x+16}-\sqrt{x} = 4\]
yes
first square both sides. so it should next look like this: 2x+16-x=4^2
u can't do that
theyr not under the same square root
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no? is it becuase they're two different terms?
oh, right! duhh. basic rules!
okay try other method...
what method?
id multiply both sides by sqrt(2x+16)+sqrt(x)
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to get: 2x+16-x = 4[sqrt(2x+16) + sqrt(x)]
x + 16 = 4(sqrt(2x+16)+sqrtx)
ok thanks
i honestly dunno what do now.. lol havent done this in a while..
same here, thats why i messed up. sorry! lemme remember and ill help you in a sec!
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