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integral of (sin (1-x) (2-cos(1-x))^4 dx
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Let u = 2 - (cos (1-x)). Then du = -sin (1 - x)dx. Go from there. You'll be integrating -u^4 du
This is called a u-substitution.
why is du=-sin (1-x)dx? I thought since subtracting the cos, and derivative of cos is -sin, that sin would be positive?
yeah, du=sin(1-x)
if you differentiate u, you get - ( - sin (1 - x) ) * (-1). The last (-1) comes from chain rule.
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so the last (-1) is from derivative of (1-x)?
To answer for verifry, yes it is.
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