Question

if f(x)=sin^2(3-x) then f'(0)????

Answer 1

hey, how's it going?

Answer 2

Hi i really need this answer:)

Answer 3

take the derivative of (sin(3-x))^2 like it was x^2, you just have to remember to multiply by the derivative of what's inside the "squared"

Answer 4

oo sick thats so helpful thanks a million

Answer 5

hah wats the answer just to confirm?

Answer 6

why dont you give me what you came up with and we'll see if it looks good

Answer 7

so i know it starts of as 2(sin3-x)

Answer 8

then multiply by the derivative of sin(3-x)

Answer 9

so the derivative of sin(3-x) is? uhm cos(3-x)? correct?

Answer 10

not quite, remember you have to multiply by the derivative of what's inside the sin

Answer 11

waah i hate calc. ok so the derivative of that is 1?

Answer 12

is it?

Answer 13

lol idk im asking u!

Answer 14

what's the derivative of 3-x, you probably know that

Answer 15

-1!!!

Answer 16

good

Answer 17

so then its 2sin(3-x)(cos3-x)(1)

Answer 18

what'd we just talk about though?

Answer 19

usually you wouldn't leave it as times 1 just so you know, that would just go away

Answer 20

f(x)=sin^2(3-x)
f'(x)= 2sin(3-x)(cos (3-x))(-1)

Evaluate for 0:
f'(0) = -2sin(3-(0))(cos(3-(0))
f'(0) = -2sin(3)cos(3)
f'(0) = 0.279415..

Answer 21

hey iparke

Answer 22

Hi, Mr. Euclid. He forgot the -1, I have no intention of stealing your thunder ;)

Answer 23

no i don't care, and yeah i was already telling him but he disappeared

Answer 24

if you want some math to do here is a test for you http://floridamao.org/PublicPages/TestArchive.aspx?qy=true&category=States&style=Limits+%26+Derivatives&year=2005

Answer 25

Ooh cool, saved to bookmarks. I really should be doing my area between two curves calc homework, funny that I choose to do other math as an effective self distraction instead of more traditional routes (video games and food).

Firefox hates this site, trying it with Chrome now.

Love the name by the way. Euclid's Fifth Postulate and hyperbolic geometry ftw.