Question

to find the acceleration vector of
x=t√
and
y=3t2−2t
when t=1 would you just take the derivative of both x and y twice?

Answer 1

\[3t^{2}\]

Answer 2

not 3t2

Answer 3

yeah if that's the position function

Answer 4

yeah if that's the position function

Answer 5

which it would say r(t) =<\[\sqrt{t}\],\[3t^{2}\]>

Answer 6

sorry trying to work with equation editor hah