Question

the integral of dt/t times root t

Answer 1

thats just ... ln t * root t

Answer 2

thanks

Answer 3

That's not correct though. If I understood correctly and you have this integral:
\[\int\limits dt/t \sqrt{t}\]
You solve it by using the exponent properties. This will add up to:
\[\int\limits dt/ t^{3/2}\]
Treating this as \[\int\limits t^{-3/2}\] you should be able to integrate from there.
If you derivate ln(t)*t you get \[\sqrt{x}/x + \ln(x)/2\sqrt{x}\]
Which is not the same integral.

Answer 4

ln(t)*root(t) obviously, misstype..

Answer 5

That's what I was thinking as well but I think rockrmol5 means:
\[\int\limits_{}\sqrt{t}/t dt=\int\limits_{}t^{-1/2}=2t^{1/2}+c\]
either way one of us is right bc ln(t)*root(t) doesn't make any sense