Question

OKSY HOW DO I FIND (X,Y,Z)....

3X+4Y+2Z=24

Answer 1

AND

(X+3)^2+Z^5+25

Answer 2

are they both part of the same system?

Answer 3

YEA THEY ARE

Answer 4

WELL WHAT I WAS DOING WAS SOLVE INDIVIDUALY LIKE 3X=24 AND THEN DIVIDING IT TO BOTH SIDES WICH GAVE ME 8 SO X=8 AND THEN I DID THAT TO Y AND Z

Answer 5

IM NOT SURE IF THATS CORRECT

Answer 6

No. What is your second equation up there equal to?

Answer 7

I GOT SOMETHING LIKE (-3,0,5)

Answer 8

AND FOR MY FRST EQUATION I GOT (8,6,12)

Answer 9

No. Those answers aren't correct. If you can tell me what your second equation is equal to then I can help you.

Answer 10

OOOH SRRY THE SEC ONE EQUALS 25 I ACCENDENTLY PUT PLUS

Answer 11

No problem. Solve your first equation for x...
x=8-(4/3)y-(2/3)z...and so...
x+3=11-(4/3)y-(2/3)z...
do you follow?

Answer 12

yea a little

Answer 13

well, this gets kind of messy, so it's important that you can get that far, because you also solve it for z & substitute each into your second equation.

Answer 14

HEHE OKAY THNX SO MUCH I JUS HAD TO LOOK AT IT A COUPLE OF TIMES TO UNDERSTAND IT THANK YU