An amusement park charges $8 admission and average of 2000 visitors per day. A survey shows that for each $1 increase in the admission cost, 100 fewer people would visit the park. a) Write an equation to express the revenue, R(x) dollars, in terms of a price increase of x dollars b) Find the coordinates of the maximum point of this function c) What admission cost gives the maximum revenue? d) How many visitors give the maximum revenue
You need to find the revenue, R(x), which is by definition, R(x) = (admission per person) x (number of people) We know that if we increase the admission per person by 1 unit, the number of people goes down 1 unit, so R(x) = (8 + 1)*(2000 - 100) If we define the variable 'x' to represent the number of increases in price, from what we've begun to establish, \[R(x)=(8+x)(2000-100x)\]Expanding gives, \[R(x)=16000+1200x-200x^2\]
The maximum point will be given for\[R'(x)=1200-200x\]Setting R'(x) to zero and solving gives,\[x=6\]The corresponding R-coordinate is then, \[R(6)=19600\]The coordinate of the maximum is therefore (6,19600).
The park should make a 6-unit increase to maximize its revenue. So the admission cost should be $14. The number of people attending would then by 19,600.
thanks so much for your help!
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