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OpenStudy (anonymous):
I need to find critical points for x^5+x^2, I've taken the derivative but cannot determine the points once i've set it equal to 0
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OpenStudy (anonymous):
f(x)=x^5+x^2? If so then f'(x)=5x^4+2x. If 5x^4+2x=0 then 0=x(0+/-{[0-(4)(2)]^(1/2)}/10. Maybe? Just took the quadratic formula, but it doesn't work very well...if at all.
OpenStudy (anonymous):
thanks...I confused you, I was supposed to be doing MVT anyway lol Thanks alot anyway, sorry
OpenStudy (anonymous):
Heh, no problem. =)
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