Question

Solve:
(4x^2 - 9)^2 - 11(4x^2 - 9) + 24 = 0.

Answer 1

\[x = \sqrt{3}\]
or
\[x=-\sqrt{3}\]
or
\[x=- \sqrt{17}/2\]
or
\[x= \sqrt{17} /2\]

Answer 2

@tropical u use da quadratic equation ok i just work it out normally and get 16x^4-116x^2+204

Answer 3

we had to solve it...

Answer 4

@ok thanx 4 the info

Answer 5

u^2 -11u +24 = 0 ; u=(4x^2 -9)
(u-3)(u-8)=0
u=3 or u=8

4x^2 -9=3
4x^2 = 12
2x= +-sqrt(12)
x= +-2sqrt(3)/2 = +-sqrt(3)

4x^2 -9=8
4x^2 =17
2x=+-sqrt(17)
x= +-sqrt(17)/2

Just another way of doing it :)