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Differentiate the function 6/lnx
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= -6/[x*(lnx)^2]
how did u get that?
You can use either quotient or chain rule. If you want to use chain rule, you’d view it as 6 * (ln x)^(-1). Then the derivative would be 6 * (-1) (ln x ) ^ (-2) * d/dx [ln x] = 6 (-1) (ln x) ^ (-2) * (1/x), If you want to use the chain rule, then you’d get (6*(1/x) – 0 * ln x)/ (ln x)^2, which is the same thing as above.
thank u!
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