Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

The function f(x)=x/(2x+1) -5 will decrease by approximately 0.6 as x decreases from 3 to 2.7. TRUE OR FALSE. How do I show the work. Not sure where to start.

OpenStudy (anonymous):

Just calculate the function when x = 3 and when x = 2.7. If f(3) is about .6 more than f(2.7), it's true

OpenStudy (anonymous):

I don't need to do the derivitive of the problem?

OpenStudy (amistre64):

The derivative is a rate of change; or how fast something is at a given point; how fast something is moving/changing. This question appears to be asking for a value of "how much" and not "how fast". But I could be mistaken... So I agree with dwob...

OpenStudy (anonymous):

x is decreasing from 3 to 2.7. Would that not be a rate of change?

OpenStudy (anonymous):

You technically could solve this with derivatives if you wanted to, but you'd find the derivative and then integrate it for no real reason. If I run and want to now how much weight I sweat off, I just weigh myself before and after. It's the same concept. Check the before (x = 3) and then check the after (x = 2.7) You don't need to know the speed that it sweat off (finding the derivative), just the total amount.

OpenStudy (anonymous):

Thanks for the info. All of the other problems I have to do, deals with the derivative, so I just assumed this one would too.

OpenStudy (amistre64):

The "slope" of the line at x=3 is -.2245 The "slope" of the line at x=2.7 = -.1997 So the slope of the line is increasing from 3 to 2.7 by .0252. But, that is not a decrease in f(x); it is a decrease in the slope of the line that is tangent to the curve at f(x) Either way, I would say it is false.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!