find Bernoulli's equation,,,,, xy'-ytgx+y^2cosx=0

Question

anonymous · Answer

I'm assuming t and g are constants? I'm also assuming that y is a function of x, i.e. one variable? Otherwise you'll have to do this as a partial differential equation (PDE) which I'm not familiar with and is rather difficult.

anonymous · Answer

If this is true, then it's not very difficult except for the integration.

gina · Answer

thn help plz

anonymous · Answer

Well, are they constants?

anonymous · Answer

Sorry, are t and g constants that is?

anonymous · Answer

Well, assuming t and g are constants, the Bernoulli equation would be this
$$xy \prime-ytgx=y^{2}cosx$$$$y \prime - ytg=y^{2}\cos(x)/x$$
However, trying to solve this equation will quickly make your head hurt as it looks like it involves the exponential integral which I know nothing about. I'll ask one of the math professors at my school tomorrow. However, the Bernoulli equation (unsolved) is what I wrote above.