Question

integrate 1/(4+x^2) x=0 , x=(2/squareroot3)

Answer 1

\[\int\limits_{0}^{2/\sqrt{3}}1/(4+x ^{2})\] =(1/4)*1/(1+(x/2)^2)
\[=1/4 *\tan^{-1} x/2\](x=0 to 2/root3)
so by putting the value of x u will get the ans as \[\pi/6\]