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Integral of 1/ sqrt(1+2x) dx ? Upper limit=12 Lower limit = 0.
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1/5 - 1 = -4/5
\[ \int\limits_{0}^{12} 1 \div \sqrt{1+2x}\] this is what it looks like. im getting 8 but the answer is 4 ..
Work: Upper limit - 1/sqrt(1 + 24) = 1/sqrt(25) = 1/5 Lower limit - 1/sqrt(1 + 0) = 1/1 = 1 Upper limit - lower limit = 1/5 - 1 = -4/5
but the answer is 4 ..
Oh, crap... I forgot how to integrate, lawl. Let's try that again...
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1 + 2x = u 2dx = du dx = du/2 1/2 * integral(1/rad(u) du) I think this is it.
Hmm, okay, thanks..
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